No clue about 2002 Q11:
The equation for the complete combustion is C3H8(g)+5O2(g) -> 3CO2(g) + 4H20(l)
50cm3 of propane is mixed with 500cm3 of oxygen and the mixture is ignited. What is the volume of the resulting gas mixtue?
A 150cm3 B 300cm3 C 400cm3 D 700cm3
I thought 1mole reacted with 1 mole (oxygen is in excess) so 50cm3 propane -> 150 cm3 of Carbon dioxide so the answer would be A 150cm3. I cant understand why the answer is C 400 cm3.
PS Sorry about all these last minute questions, getting quite nervous now!!
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2002 - Multiple Choice - Q11
Started by jamiep, May 30 2005 11:12 AM
6 replies to this topic
#2
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Brendan
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Posted 30 May 2005 - 11:19 AM
Remember there is also unreacted O2.
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#3
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Posted 30 May 2005 - 11:21 AM
i think the answer is 400cm
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#4
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Posted 30 May 2005 - 11:28 AM
Could you explain why the answer is 400cm3?
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Brendan
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Posted 30 May 2005 - 11:31 AM
50cm3 propane and 250cm3 oxygen (5x50) reacts, and 100cm3 of oxygen is left unreacted (5mol-3mol=2mol, 2x50=100).
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Posted 30 May 2005 - 11:35 AM
QUOTE(tupacshakur @ May 30 2005, 11:21 AM)
i think the answer is 400cm
QUOTE(bred @ May 30 2005, 11:31 AM)
50cm3 propane and 250cm3 oxygen (5x50) reacts, and 100cm3 of oxygen is left unreacted (5mol-3mol=2mol, 2x50=100).
I did not understand that it was asking for me to add on the oxygen.
Hope I don't get tricked tomorrow!
#7
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Posted 30 May 2005 - 02:42 PM
Normally you just ignore the reactant in excess and use the other reactant to figure out the calculations, but the question asks for the TOTAL VOLUME, so I suppose you do have to take into account the unreacted oxygen.
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