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MATHS EXAM 2005 - HSN forum - Page 11

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MATHS EXAM 2005


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#201 Dave

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Posted 20 May 2005 - 09:35 PM

though i wouldnt bet my last tenner on it

If i am not here i am somewhere else



#202 tupacshakur

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Posted 21 May 2005 - 04:27 PM

oh crap, im getting nervous now cos i think i MITE have forgotton to put the "+ c" after i integrated in question 1 in paper 2

Maybe its just after exam nerves but im thinking bak and i still cant remember if i did put the "+ c" in.

how many marks do u lose for not putting plus c in?
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#203 erin

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Posted 21 May 2005 - 04:57 PM

QUOTE(gary @ May 20 2005, 12:01 PM)
Yes I got 36 units wasn't sure about that question paper 1 sucked.

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I agree! I thought that that was the hardest paper 1 i had ever done (and people are saying it was easy!!!! AHHHHHHHHHHH!)

#204 Pooch

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Posted 21 May 2005 - 05:17 PM

QUOTE(tupacshakur @ May 21 2005, 05:27 PM)
oh crap, im getting nervous now cos i think i MITE have forgotton to put the "+ c" after i integrated in question 1 in paper 2

Maybe its just after exam nerves but im thinking bak and i still cant remember if i did put the "+ c" in.

how many marks do u lose for not putting plus c in?

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I can't imagine them taking any more than one mark off rolleyes.gif

#205 The Wedge Effect

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Posted 21 May 2005 - 06:53 PM

Yeah, they only deduct one mark if you miss something like "+ C" or "dx", something like that. That what I used to always forget and I lost only one mark by doing that...lucky. However, I'm panicking about the function combination question "h(x)=g(f(x))" as I always make mistakes in those...sad.gif Even more panicky about the differentiation question. How many marks do you reckon they will take off for having 7³=313 instead of 7³=343? sad.gif

#206 tupacshakur

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Posted 21 May 2005 - 11:14 PM

surley u cant lose a mark for not writing dx!
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#207 CutieBum

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Posted 22 May 2005 - 01:04 AM

I noticed the discussion about P2, Q4b earlier in the paper. I got 50.9 for the angle also. Those who thought it was 36 something? The angle doesn't look like it could be any less than 45degrees but I could be wrong.

#208 The Wedge Effect

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Posted 22 May 2005 - 09:04 AM

QUOTE(tupacshakur @ May 22 2005, 12:14 AM)
surley u cant lose a mark for not writing dx!

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Yeah, you can lose marks for not writing "dx" or "+ C". Don't believe me? Ask your Maths teacher next time you see him/her. Anyway, about the angle question, I got 80 something degree. I think my answer is correct however...

#209 david__taylor

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Posted 22 May 2005 - 09:05 AM

QUOTE(Mr H @ May 20 2005, 08:44 PM)
Paper 2 Q8

I am writing out solutions which I will soon put on the web.

Just done P2 Q8 and proved the answer but can't see how it is worth 5 marks.

Can anyone check this and see if I missed something?

Cheers!

ksin2x = sinx

2ksinxcosx = sinx (double angle substitution)

2kcosx = 1  (divide by sinx)

cosx = 1/2k

Proved!

Generous at 4 marks I thought but 5?!*?

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Or you could do:

2ksinxcosx = sinx, subtract:

2ksinxcosx - sinx = 0

sinx(2kcosx - 1) = 0
so sinx = 0 and 2kcosx - 1 = 0
therfore cosx = 1/2k.

Harder but also correct

Ignore this post as people have already talked about it.

#210 The Wedge Effect

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Posted 22 May 2005 - 09:32 AM

OK, I worked out the solutions for question 4 in 2nd paper as so many people had been asking for them, and the angle came out to 50.9 degree.gif so I realised I got the wrong answer. >=( Solution is below. Vector names have to have arrows on the top but crappy keyboard lacks arrows (or huge brackets for component form)

4. a)TA=a-t
= (-5, 15, 1)

TB=b-t
=(-40, 15, 2)



b) TA.TB=ta base1.gif tb base1.gif + ta base2.gif tb base2.gif +ta base3.gif tb base3.gif
=((-5)x(-40))+(15²)+(1x2)
= 427

|TA|= sqrt.gif 251
|TB|= sqrt.gif 1829


Cos theta.gif = (TA.TB)/(|TA|x|TB|)
= 427/( sqrt.gif 251x sqrt.gif 1829)
theta.gif almost.gif 50.9 degree.gif

Some lines of working were missed out as I couldn't be bothered to type them. tongue.gif
If you notice any mistakes, please do not hesitate to let me know and I'll edit it. wink.gif

#211 tupacshakur

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Posted 22 May 2005 - 10:19 AM

QUOTE(Wedge37 @ May 22 2005, 09:32 AM)
OK, I worked out the solutions for question 4 in 2nd paper as so many people had been asking for them, and the angle came out to 50.9 degree.gif so I realised I got the wrong answer. >=( Solution is below. Vector names have to have arrows on the top but crappy keyboard lacks arrows (or huge brackets for component form)

4. a)TA=a-t
                    = (-5, 15, 1)

                TB=b-t
                    =(-40, 15, 2)



    b) TA.TB=ta base1.gif tb base1.gif + ta base2.gif tb base2.gif +ta base3.gif tb base3.gif
                          =((-5)x(-40))+(15²)+(1x2)
                          = 427

                  |TA|= sqrt.gif 251
                  |TB|= sqrt.gif 1829


                    Cos  theta.gif = (TA.TB)/(|TA|x|TB|)
                                      = 427/( sqrt.gif 251x sqrt.gif 1829)
                          theta.gif  almost.gif 50.9 degree.gif

Some lines of working were missed out as I couldn't be bothered to type them. tongue.gif
If you notice any mistakes, please do not hesitate to let me know and I'll edit it. wink.gif

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oh crap, i dont know where i went wrong. I got 36.9 degrees but im hopeful of atleast 3 marks.

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#212 Colin

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Posted 22 May 2005 - 10:30 AM

QUOTE(tupacshakur @ May 22 2005, 10:19 AM)
QUOTE(Wedge37 @ May 22 2005, 09:32 AM)
OK, I worked out the solutions for question 4 in 2nd paper as so many people had been asking for them, and the angle came out to 50.9 degree.gif so I realised I got the wrong answer. >=( Solution is below. Vector names have to have arrows on the top but crappy keyboard lacks arrows (or huge brackets for component form)

4. a)TA=a-t
                     = (-5, 15, 1)

                 TB=b-t
                     =(-40, 15, 2)



    b) TA.TB=ta base1.gif tb base1.gif + ta base2.gif tb base2.gif +ta base3.gif tb base3.gif
                           =((-5)x(-40))+(15²)+(1x2)
                           = 427

                   |TA|= sqrt.gif 251
                   |TB|= sqrt.gif 1829


                    Cos  theta.gif = (TA.TB)/(|TA|x|TB|)
                                      = 427/( sqrt.gif 251x sqrt.gif 1829)
                           theta.gif  almost.gif 50.9 degree.gif

Some lines of working were missed out as I couldn't be bothered to type them. tongue.gif
If you notice any mistakes, please do not hesitate to let me know and I'll edit it. wink.gif

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oh crap, i dont know where i went wrong. I got 36.9 degrees but im hopeful of atleast 3 marks.

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I also followed all those steps and got something like 70 degrees. Hopefully will still get 3 marks though


#213 YIC

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Posted 22 May 2005 - 10:39 AM

well, at least I done the method correctly but I still got the wrong answer. I am quite confident I got the coordinates as they look familiar and I must have checked it a few times. Hopefully I got 5/7 PLEAAAASSSEEEE!!! GOD





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