

MATHS EXAM 2005
Started by milnedaniel, May 19 2005 09:50 PM
212 replies to this topic
#21
Posted 20 May 2005 - 12:01 PM
Yes I got 36 units wasn't sure about that question paper 1 sucked.
#22
Posted 20 May 2005 - 12:01 PM
Same as me davey boy, paper 1 was hard(for me, not a maths genius). I need a c so lets nope the pass marks pretty low

#23
Posted 20 May 2005 - 12:04 PM
QUOTE(HatingHighers @ May 20 2005, 11:55 AM)
I got
Paper 2
2)b)i) -13/85
b)ii) -84/13
c)i) (2,3)
7) 2.87
11)a) Put it into the equation, it came to zero
b) Synthetic division, used discriminant, got p<or=to -1, p>or=to 3
Paper 2
2)b)i) -13/85
b)ii) -84/13
c)i) (2,3)
7) 2.87
11)a) Put it into the equation, it came to zero
b) Synthetic division, used discriminant, got p<or=to -1, p>or=to 3
wooo yea! i got 2.87... and rounded up to 2.9 which is less than 3

and got those answers for 2b!

#24
Posted 20 May 2005 - 12:05 PM
I doubt it will change much this paper was harder than last year.
What about answers to paper 1.
What about answers to paper 1.
#25
Posted 20 May 2005 - 12:06 PM
Ok I got 14.5 for Q.10 is the correct answer 13.5.
#26
Posted 20 May 2005 - 12:08 PM
It definately was 36 units, checked it on graphics calculator.
Thought both papers went well, Paper One was a bit harder than Paper 2 I thought.
My theories for pretty much all the questions were sound I think, but I've made a few errors , llike not putting +C after integration
and the graph sketching forgetting to add 3 etc.
Thought both papers went well, Paper One was a bit harder than Paper 2 I thought.
My theories for pretty much all the questions were sound I think, but I've made a few errors , llike not putting +C after integration

#27
Posted 20 May 2005 - 12:10 PM
In the recurrance relations question in paper one, did everyone work k out to =1?
You'll never bring me down, cos' i'm so far above you...
#28
Posted 20 May 2005 - 12:11 PM
How did people do that question I got very confused.
#29
#33
Posted 20 May 2005 - 12:20 PM
QUOTE(gary @ May 20 2005, 01:11 PM)
Hail to the the Chief for making the answer -1/4.
That's what I said but nasty friends were telling me it was positive.
Very annoyed though that there wasnt any optimisation or completing the square etc. I'm a pro at those.
Also, the whole a.(a+b+c+) thing, what's that all about?
#34
Posted 20 May 2005 - 12:21 PM
QUOTE(*Suz* @ May 20 2005, 12:10 PM)
I didnt get this question right, I think i must have dont eh same as you, did you differentiate etc then turns out to be one?
The right answer is that you take the expression its something like (3x...) and make it into two brackets, one solution is -1/4 and the other is 2, therefore the answer is 2 as it does not recur, while -1/4 does recur (recurrance happens when x is in between 1 and -1)
#35
Posted 20 May 2005 - 12:22 PM
What did everyone get for these:
Paper 1
1.
2.
4.
5.
6.
7.
8.
11a.
Paper 1
1.
2.
4.
5.
6.
7.
8.
11a.
#37
Posted 20 May 2005 - 12:23 PM
I got 14.5 for that someone said it was 13.5 so I don't know.
#38
Posted 20 May 2005 - 12:23 PM
QUOTE(jondom @ May 20 2005, 01:20 PM)
QUOTE(gary @ May 20 2005, 01:11 PM)
Hail to the the Chief for making the answer -1/4.
That's what I said but nasty friends were telling me it was positive.
Very annoyed though that there wasnt any optimisation or completing the square etc. I'm a pro at those.
Also, the whole a.(a+b+c+) thing, what's that all about?
a.(a+b+c) = a.a + a.b + a.c?
a.a = 3*3
a.b = 0
a.c = 3 * 2 * cos(sin-1(2/3))
and add 'em together. That's what I did...

Comes to 13.5.
<MrBob> I hate Uni. At least in film studies we get to talk about Fight Club.
<@X-Factor> Wouldnt you be breaking the first 2 rules?
<@X-Factor> Wouldnt you be breaking the first 2 rules?

#39
Posted 20 May 2005 - 12:26 PM
QUOTE(pseudotoxic @ May 20 2005, 12:23 PM)
QUOTE(jondom @ May 20 2005, 01:20 PM)
QUOTE(gary @ May 20 2005, 01:11 PM)
Hail to the the Chief for making the answer -1/4.
That's what I said but nasty friends were telling me it was positive.
Very annoyed though that there wasnt any optimisation or completing the square etc. I'm a pro at those.
Also, the whole a.(a+b+c+) thing, what's that all about?
a.(a+b+c) = a.a + a.b + a.c?
a.a = 3*3
a.b = 0
a.c = 3 * 2 * cos(sin-1(2/3))
and add 'em together. That's what I did...

Comes to 13.5.


WWE RAW IS WAR
#40
Posted 20 May 2005 - 12:27 PM
I never got that then don't see how sin comes into it.
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users