I am stuck on this question, can anyone shed any light upon it before the exam tomorrow?
Thanks


2002 Winter Diet
Started by Blind, May 19 2005 07:44 PM
4 replies to this topic
#1
Posted 19 May 2005 - 07:44 PM
#2
Posted 19 May 2005 - 07:50 PM
logap=cos2x
logar=sin2x
Using log rules:
asin2x = r
acos2x = p
Multiplying together:
acos2x. asin2x = pr
acos2x + sin2x = pr
a1 = pr
Note: cos2x + sin2x = 1
logar=sin2x
Using log rules:
asin2x = r
acos2x = p
Multiplying together:
acos2x. asin2x = pr
acos2x + sin2x = pr
a1 = pr
Note: cos2x + sin2x = 1
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#3
Posted 19 May 2005 - 07:59 PM
logap=cos2x
logar=sin2x
Using y=logax <=> x=ay:
p=acos2x and r=asin2x
So pr=(acos2x) x (asin2x)
Using laws of multiplying indices:
pr=a(cos2x + sin2x)
pr=a1
pr=a
logar=sin2x
Using y=logax <=> x=ay:
p=acos2x and r=asin2x
So pr=(acos2x) x (asin2x)
Using laws of multiplying indices:
pr=a(cos2x + sin2x)
pr=a1
pr=a
H tends 2 infinity
---------------------------------
Never argue with an idiot. They drag you down to their level then beat you with experience.
#4
Posted 19 May 2005 - 08:00 PM
GAZUMPED!!!
Shouldn't have gone for a drink mid-post!
(Did get to practice sub and superscripts though!)
Shouldn't have gone for a drink mid-post!
(Did get to practice sub and superscripts though!)
H tends 2 infinity
---------------------------------
Never argue with an idiot. They drag you down to their level then beat you with experience.
#5
Posted 19 May 2005 - 09:27 PM
Cheers.
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