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# Log Question

Started by gary, May 19 2005 03:00 PM

13 replies to this topic

### #1

Posted 19 May 2005 - 03:00 PM

In the exam is it possible there will be a question where it asks:

find an equation of the line in the form y=mx+c

then

hence find the vaues of the constants a and b in the realationship y=ax^b

or are these questions too long to be examined.

find an equation of the line in the form y=mx+c

then

hence find the vaues of the constants a and b in the realationship y=ax^b

or are these questions too long to be examined.

### #2

Posted 19 May 2005 - 03:01 PM

It is possible. I think the question you should be asking is, is it likely?

Half ideas,half quality, half a million pound law suit!

### #3

Posted 19 May 2005 - 03:02 PM

Is it likely?

### #5

Posted 19 May 2005 - 03:05 PM

What past paper apart from 2000 is it in i can't see it?

### #6

Posted 19 May 2005 - 03:08 PM

QUOTE(gary @ May 19 2005, 03:05 PM)

the last question in paper 1 of 2002

it hasnt appeared since then so im guessing its highly likley it will come up this year.

on the topic of 2002, how the hell do u do question 4 in 2002 paper 1 !

WWE RAW IS WAR

### #7

Posted 19 May 2005 - 03:11 PM

er...work out the centre of the cricle using the formula list and then use this to find m1. work out m2 which is perp. and then sub (2,3) and m2 into equation of staright line

### #9

Posted 19 May 2005 - 03:17 PM

holy god i am an idiot.

Q4 okay... tan45=m

m = 1

the derivative of the curve will equal 1, so jut solve it!

i.e 4x-7=1

x=2

sub x=2 into original curve and there you have it

Q4 okay... tan45=m

m = 1

the derivative of the curve will equal 1, so jut solve it!

i.e 4x-7=1

x=2

sub x=2 into original curve and there you have it

### #10

Posted 19 May 2005 - 03:19 PM

ok ok. Calm down.

Half ideas,half quality, half a million pound law suit!

### #11

Posted 19 May 2005 - 03:19 PM

everything is calm....

### #12

Posted 19 May 2005 - 03:30 PM

QUOTE(YIC @ May 19 2005, 03:17 PM)

holy god i am an idiot.

Q4 okay... tan45=m

m = 1

the derivative of the curve will equal 1, so jut solve it!

i.e 4x-7=1

x=2

sub x=2 into original curve and there you have it

Q4 okay... tan45=m

m = 1

the derivative of the curve will equal 1, so jut solve it!

i.e 4x-7=1

x=2

sub x=2 into original curve and there you have it

yeah but how the hell do you know to "differentiate" the equation in the first place.

what clues do they gove to tell u to do that , i cant see any

WWE RAW IS WAR

### #13

Posted 19 May 2005 - 03:35 PM

well, the question says "tan to the curve makes an angle of 45 degrees with +ve direction of x-axis" which is really meaning "the gradient." You would also know that the derivative is the gradient of a tangent (to the curve ).

It is just about knowing and recognising certain rules

It is just about knowing and recognising certain rules

### #14

Posted 19 May 2005 - 03:38 PM

QUOTE(YIC @ May 19 2005, 03:35 PM)

well, the question says "tan to the curve makes an angle of 45 degrees with +ve direction of x-axis" which is really meaning "the gradient." You would also know that the derivative is the gradient of a tangent (to the curve ).

It is just about knowing and recognising certain rules

It is just about knowing and recognising certain rules

thanks

WWE RAW IS WAR

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