In question 139(a) should the separation of the fringes be calculated by dividing the separation for 11 fringes /11 ? To get the answer given in the PP solutions you would have to use the separation for the 11 fringes. Is there an error or am I over-looking something ?
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AH Physics Paper 2004
Started by Glasgow_girl_17, Apr 16 2005 04:56 PM
17 replies to this topic
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Posted 16 April 2005 - 05:04 PM
out of interest how fare through the course are you because i have just touched fringes this week
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Posted 16 April 2005 - 07:28 PM
I'm just looking at the question just now, but surely you divide by 10?
I'll work through the question in a minute and see.
I'll work through the question in a minute and see.
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Posted 16 April 2005 - 07:34 PM
Yeh, you definitely divide by 10.
There are 11 fringes, so there are 10 spaces between the finges. so delta X = 0.0026 m
d=0.52 x 10 -3 m
D = 2.00m
delta (X) = lambda (D)/d
lambda = delta (X) d/D
lambda = 676 nm
There are 11 fringes, so there are 10 spaces between the finges. so delta X = 0.0026 m
d=0.52 x 10 -3 m
D = 2.00m
delta (X) = lambda (D)/d
lambda = delta (X) d/D
lambda = 676 nm
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Posted 16 April 2005 - 07:38 PM
QUOTE(Dave @ Apr 16 2005, 06:04 PM)
out of interest how fare through the course are you because i have just touched fringes this week
In my class we did unit 3 first and then unit 1, so we are currently doing unit 2 which I think is probably the hardest unit, although it's not too bad.
We just have self inductance to do.
500 posts and counting.
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If you can keep your head when all about you
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Posted 16 April 2005 - 09:48 PM
Thanks, I got the answer but I done it a different way from you. Taking m=o, and m= +/- 5, and dividing the distance by 2. Which is the same, I guess.
Have you done question 11(iii) in the 2003 Exam ? My course notes (both Scholar and other) have no examples like this. Is it a problem solving question? Any help would be great.
Has everyone finished their Investigations ?
Thanks.
Have you done question 11(iii) in the 2003 Exam ? My course notes (both Scholar and other) have no examples like this. Is it a problem solving question? Any help would be great.
Has everyone finished their Investigations ?
Thanks.
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Posted 17 April 2005 - 01:05 AM
i have done first draft and will make changes for monday..i hope
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Posted 17 April 2005 - 10:36 AM
QUOTE(Glasgow_girl_17 @ Apr 16 2005, 10:48 PM)
Thanks, I got the answer but I done it a different way from you. Taking m=o, and m= +/- 5, and dividing the distance by 2. Which is the same, I guess.
Have you done question 11(iii) in the 2003 Exam ? My course notes (both Scholar and other) have no examples like this. Is it a problem solving question? Any help would be great.
Has everyone finished their Investigations ?
Thanks.
Have you done question 11(iii) in the 2003 Exam ? My course notes (both Scholar and other) have no examples like this. Is it a problem solving question? Any help would be great.
Has everyone finished their Investigations ?
Thanks.
That's not problem solving and is definitely in the course.
When light enters are more optically dense media such as glass or perspex it undergoes a change of phase of
radians. From that you can work out that for constructive interference PD = (m+0.5) lambda and for destructive interference PD = m lambda. Do you understand why?I've finished my physics investigation, just need some final checking, I emailed my teacher with it yesterday and she should get back to me on Monday about it. What is everyone's investigation on? Mine is on the physics of stretched strings.
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Or being hated, don't give way to hating,
And yet don't look too good, nor talk too wise:
Yours is the Earth and everything that's in it,
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If you can keep your head when all about you
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If you can trust yourself when all men doubt you
But make allowance for their doubting too,
If you can wait and not be tired by waiting,
Or being lied about, don't deal in lies,
Or being hated, don't give way to hating,
And yet don't look too good, nor talk too wise:
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Posted 17 April 2005 - 12:18 PM
Yes, I thought that was the answer too. However, the solutions state that for constructive interference Optical Path Difference = (n+0.5)x lambda. Surely 'n' represents the refractive index rather than an integer. Is this an error of the SQA's part ?
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Posted 17 April 2005 - 12:24 PM
is m not for refractive index now
i got slightly confused at that bit...partly because i haven't truelly covered it yet
i got slightly confused at that bit...partly because i haven't truelly covered it yet
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Posted 17 April 2005 - 12:36 PM
I don't have a clue what the formula means, but this is what says in the data booklet:
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Posted 17 April 2005 - 02:08 PM
yeah i thought that
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Posted 17 April 2005 - 03:02 PM
Are Physics candidates supposed to be given a data booklet !?!
I have never heard about this - is there anything else I should have been given and will we be able to use this booklet in the exam and NABs ?
I have never heard about this - is there anything else I should have been given and will we be able to use this booklet in the exam and NABs ?
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Posted 17 April 2005 - 04:18 PM
lol no, the data booklet doesn't come in till next year.
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If you can keep your head when all about you
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Or being hated, don't give way to hating,
And yet don't look too good, nor talk too wise:
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Posted 17 April 2005 - 04:40 PM
Anyone got a clue about the past paper solution saying that constructive interference = (n+ 1/2) lambda, do you think they have taken 'n' as an integer rather than the refractive index ?
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Posted 17 April 2005 - 04:44 PM
The refractive index is written as "n" or "ยต" (the Greek letter mu).
"m" is an integer in this case.
"m" is an integer in this case.
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If you can keep your head when all about you
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Yours is the Earth and everything that's in it,
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If you can keep your head when all about you
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If you can wait and not be tired by waiting,
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Or being hated, don't give way to hating,
And yet don't look too good, nor talk too wise:
Yours is the Earth and everything that's in it,
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#17
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Posted 17 April 2005 - 04:47 PM
I was looking through my notes for unit 3 there and all this stuff was just before "Thin films" and in the area all about interference by division of amplitude.
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If you can keep your head when all about you
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And yet don't look too good, nor talk too wise:
Yours is the Earth and everything that's in it,
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If you can keep your head when all about you
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If you can trust yourself when all men doubt you
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Or being hated, don't give way to hating,
And yet don't look too good, nor talk too wise:
Yours is the Earth and everything that's in it,
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Posted 17 April 2005 - 05:01 PM
Yes, It doesn't really explain the PP's solution though.
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