See for question 1 a) am i right in thinking that you re-arrange the equation as y=mx+c? but if i do this then it all goes a bit wonky! So how do u find the value of 'a'??

and for qustion b) would you just use M=tan

tan 30

and so on.........??

Also how on earth do u do question 5 in this paper please??!?

Help is much appreciated !!

Ta !

**0**

# 2004 - Paper 2 - Question 1 and 5

Started by JiLL, Apr 14 2005 05:13 PM

8 replies to this topic

### #1

Posted 14 April 2005 - 05:13 PM

beast

### #2

Posted 14 April 2005 - 05:29 PM

Ok, for 1a,

You have the equation x-2y = 0.

Rewrite this as y = -x/-2

Which is y = x / 2

Pick a value - i.e. when x = 1, and this gives you y is a half. This allows you to draw a triangle and use Tan a = opposite/adjacent.

For b) all you do is add 30 degrees to what you worked out as 'a' and take the tan of it.

For 5, you take the derivative and let it equal 12.

So you have 12x - 3x

Bring everything to one side and you get:

-3x

Multiply by minus 1 to get rid of the -3x

You get:

3x

Take out common factor of 3.

3(x

Factorise:

3(x - 2)(x - 2)

Value of x = 2

You have the equation x-2y = 0.

Rewrite this as y = -x/-2

Which is y = x / 2

Pick a value - i.e. when x = 1, and this gives you y is a half. This allows you to draw a triangle and use Tan a = opposite/adjacent.

For b) all you do is add 30 degrees to what you worked out as 'a' and take the tan of it.

For 5, you take the derivative and let it equal 12.

So you have 12x - 3x

^{2}= 12Bring everything to one side and you get:

-3x

^{2}+ 12x - 12 = 0Multiply by minus 1 to get rid of the -3x

^{2}You get:

3x

^{2}- 12x + 12 = 0Take out common factor of 3.

3(x

^{2}- 4x + 4) = 0Factorise:

3(x - 2)(x - 2)

Value of x = 2

### #3

Posted 14 April 2005 - 05:35 PM

To do part b. You know x = 2. So stick this in your original equation (6x

Coordinates are (2, 16). You know gradient is 12.

Your y - b = m(x - a)

a = 2, b = 16 and m = 12.

You end up with equation: y = 12x - 8.

^{2}- x^{3}and you get 16.Coordinates are (2, 16). You know gradient is 12.

Your y - b = m(x - a)

a = 2, b = 16 and m = 12.

You end up with equation: y = 12x - 8.

### #4

Posted 14 April 2005 - 05:35 PM

Sorry, but for 1a)

i dont really understand what the opposite and adjacent values would be in this case???

arrh!

Ta 4 question 5, i now understand it!

i dont really understand what the opposite and adjacent values would be in this case???

arrh!

Ta 4 question 5, i now understand it!

beast

### #5

Posted 14 April 2005 - 05:46 PM

Ok, I'll try to clarify. You have an equation of a line. You can pick any x coordinate and and stick it in your equation and get an answer for y.

For example, say you choose x = 1. You stick it in and you get y = 0.5

This tells you that you have a line from the origin, 1 along and 0.5 up.

It's a triangle.

[attachmentid=62]

For example, say you choose x = 1. You stick it in and you get y = 0.5

This tells you that you have a line from the origin, 1 along and 0.5 up.

It's a triangle.

[attachmentid=62]

### #6

Posted 14 April 2005 - 05:54 PM

woo hoo i sooooooooo get it now!

I'm kicking myself for how silly i'm beng!!

Sorry for any inconveinence that this may have caused

I'm kicking myself for how silly i'm beng!!

Sorry for any inconveinence that this may have caused

beast

### #7

Posted 14 April 2005 - 06:12 PM

Don't be daft you never caused any inconvienance, I'm here to help - and even want to be a maths teacher .

### #8

Posted 14 April 2005 - 06:55 PM

o thats good!

Well rather u than me!!

lol

Well rather u than me!!

lol

beast

### #9

Posted 14 April 2005 - 08:28 PM

If you need any more help with the 2004 paper I put some answers together last year before the official marking schemes came out.

http://www.bearsdenacademy.org/index.php?t...news&newsid=173

I've not put working for the easier questions, but there is working for the some of the slightly harder questions.

For 1 a) you don't actually have to even draw the triangle, just work out m to be 0.5 and use the formula m = Tan (THETA)

http://www.bearsdenacademy.org/index.php?t...news&newsid=173

I've not put working for the easier questions, but there is working for the some of the slightly harder questions.

For 1 a) you don't actually have to even draw the triangle, just work out m to be 0.5 and use the formula m = Tan (THETA)

Click here to visit the Bearsden Academy Website

If you can keep your head when all about you

Are losing theirs and blaming it on you,

If you can trust yourself when all men doubt you

But make allowance for their doubting too,

If you can wait and not be tired by waiting,

Or being lied about, don't deal in lies,

Or being hated, don't give way to hating,

And yet don't look too good, nor talk too wise:

Yours is the Earth and everything that's in it,

And--which is more--you'll be a Man, my son!

If you can keep your head when all about you

Are losing theirs and blaming it on you,

If you can trust yourself when all men doubt you

But make allowance for their doubting too,

If you can wait and not be tired by waiting,

Or being lied about, don't deal in lies,

Or being hated, don't give way to hating,

And yet don't look too good, nor talk too wise:

Yours is the Earth and everything that's in it,

And--which is more--you'll be a Man, my son!

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